Derivative

Derivatives of many functions
TheslopeofthetangentofafunctionatsomepointDerivativeofinversefunction:

\begin{align}
x & =f(y) \
1 & =f'(y)y' \
y' & =\frac{1}{f'(y)} \
& =\frac{1}{f'(f^{-1}(x))}
\end

Toshowafunctionisdifferentiableat$a$,show$f(a)=f(a+)$Youcantreat$dydx$asafractionandmoveitaroundTogetthepercentagechangein$x$,find$dxx$Ifyouhave$dx$equaltosomethingelse,probablyuseadifferentexpressionfor$x$fortherightside>[!example]sphereexample>Given$r=21$,$dr=0.07$,findthepercentagechangeinvolumeofasphere>

\begin{align}
V & =\frac{4}{3}\pi r^{3} \
\frac{ \mathrm{d}V }{ \mathrm{d}r } & =4\pi r^{2} \
\mathrm{d}V & =4\pi r^{2}\mathrm{d}r \
\frac{\mathrm{dV}}{V} & =\frac{4\pi r^{2}\mathrm{d}r}{\frac{4}{3}\pi r^{3}} \
& =\frac{3}{r}\mathrm{d}r \
& =\frac{3}{21}(0.07) \
& =1%
\end

- Kinda the opposite of Integral ## Mean Value Theorem - If $f(x)$ is cts on $[a,b]$ and $f(x)$ is differentiable on $(a,b)$, then $\exists c \in (a,b)$ s.t. $f'(c)=\frac{f(b)-f(a)}{b-a}$ - In other words, if you draw a line between b and a, there's a value in between such that the derivative is parallel - <style> .container {font-family: sans-serif; text-align: center;} .button-wrapper button {z-index: 1;height: 40px; width: 100px; margin: 10px;padding: 5px;} .excalidraw .App-menu_top .buttonList { display: flex;} .excalidraw-wrapper { height: 800px; margin: 50px; position: relative;} :root[dir="ltr"] .excalidraw .layer-ui__wrapper .zen-mode-transition.App-menu_bottom--transition-left {transform: none;} </style><script src="https://cdn.jsdelivr.net/npm/react@17/umd/react.production.min.js"></script><script src="https://cdn.jsdelivr.net/npm/react-dom@17/umd/react-dom.production.min.js"></script><script type="text/javascript" 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window.addEventListener("resize",e),()=>window.removeEventListener("resize",e)},[t]),React.createElement(React.Fragment,null,React.createElement("div",{className:"excalidraw-wrapper",ref:t},React.createElement(ExcalidrawLib.Excalidraw,{ref:e,width:n.width,height:n.height,initialData:InitialData,viewModeEnabled:!0,zenModeEnabled:!0,gridModeEnabled:!1})))},excalidrawWrapper=document.getElementById("Derivative_2025-10-06_0938.44.excalidraw.md1");ReactDOM.render(React.createElement(App),excalidrawWrapper);})();</script> - Special case: $f(a)=f(b)\implies f'(c)=0$ for $c \in (a,b)$ (Rolle's theorem) - There could be many examples of c - Special case: $f(x)=f(a)+\left( \frac{f(b)-f(a)}{b-a} \right)(x-a)$ (it's a straight line) - Every point $x \in (a,b)$ satisfies MVT - Also - if $f'(x)=0,\forall x \in (a,b)$, then $f$ is constant on $(a,b)$ - if $f'(x)>0,\forall x \in (a,b)$, then $f$ is increasing on $(a,b)$ - if $f'(x)<0,\forall x \in (a,b)$, then $f$ is decreasing on $(a,b)$ ## Finding Tangent to a Curve Passing a Line That's Not on the Curve - let point of tangency be $(a,f(a))$ - Use [[F0 - Glossary/Concrete Concepts/Linear Approximation\|Linear Approximation]] formula, then sub $x,y$, solve for a